tag:blogger.com,1999:blog-4066419901135631580.post9116534597108530595..comments2024-02-16T14:41:49.869+07:00Comments on Mechanical Design Handbook: Numerical Methods - First derivative using Excel formulaUnknownnoreply@blogger.comBlogger2125tag:blogger.com,1999:blog-4066419901135631580.post-13419749072723161942009-09-01T22:21:18.853+07:002009-09-01T22:21:18.853+07:00Hi leoo,
I would extend the table and calculate f...Hi leoo,<br /><br />I would extend the table and calculate f(x at i-1) and f(x at i-2) like this...<br /><br />f'(0 deg) = [-f(2.5 deg) + 8xf(1.25 deg) - 8xf(-1.25 deg) + f(-2.5 deg)]/(12x0.021816616) x 5.235987756 = 0.00230668 mm/s<br /><br />also for f'(1 deg) can be calculated from<br />f'(1.25 deg) = [-f(3.75 deg) + 8xf(2.5 deg) - 8xf(0 deg) + f(-1.25 deg)]/(12x0.021816616) x 5.235987756 = 1.405807453 mm/s<br /><br />We can compare this approximated values with the exact solution.<br /><br />f'(theta) = hm/bm[1 - cos(2*pi*theta/bm)] x omega<br /><br />from this formula we get<br />f'(0 deg) = 0 mm/s<br />f'(1.25 deg) = 1.403529172 mm/s<br /><br />AkeAke appshttps://www.blogger.com/profile/11820322351873655118noreply@blogger.comtag:blogger.com,1999:blog-4066419901135631580.post-39431460509273598462009-08-31T17:03:25.625+07:002009-08-31T17:03:25.625+07:00So how do you calculate for the derivative for poi...So how do you calculate for the derivative for points i = 1 and i = 2? Since the formula requires values for f(x at i-1) and f(x at i-2).<br /><br />Hoping for your reply asap. Hehe. I'm finishing my lab report for tomorrow.leoohttps://www.blogger.com/profile/15819942050252379092noreply@blogger.com