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How to Calculate Belt Conveyor Acceleration Time (Step-by-Step)

Starting a belt conveyor is not only about steady-state motor power. In many industrial applications, acceleration time is a critical design parameter that directly affects:

  • Motor starting torque
  • Gearbox stress
  • Belt tension and slip
  • VFD sizing and ramp settings

This article explains how to calculate belt conveyor acceleration time step-by-step using practical engineering methods and a realistic worked example.

Technical diagram showing belt conveyor velocity ramping up over acceleration time

Figure 1: The "Soft Start" ramp. Controlling Acceleration Time (tacc) reduces mechanical shock and prevents the belt from lifting off the idlers .

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1. Why Acceleration Time Matters

If a conveyor accelerates:

  • Too fast → high shock loads, belt slip, gearbox damage
  • Too slow → unnecessary cycle time and reduced productivity

Correct acceleration time ensures smooth startup, controlled belt tension, and acceptable motor torque.


2. Basic Parameters Required

Conveyor data

  • Belt speed, v (m/s)
  • Total moving mass, mtotal (kg)
  • Drive pulley diameter, D (m)

Drive system

  • Gearbox ratio, i
  • Gearbox efficiency, ηg
  • Motor torque capability

Assumptions

  • Uniform acceleration (linear ramp)
  • No belt slip
  • Motor torque is approximately constant during acceleration

3. Step 1 – Determine Target Belt Speed

The final belt speed is specified by the process:

v = required belt speed (m/s)

Typical industrial belt conveyors operate between 0.5 m/s and 2.5 m/s.


4. Step 2 – Calculate Required Linear Acceleration

Acceleration is defined as:

a = v / t

  • a = linear acceleration (m/s2)
  • t = acceleration time (s)

At this stage, t is unknown and will be verified against motor torque capability.


5. Step 3 – Calculate Acceleration Force

Newton’s second law applies to conveyor acceleration. However, a belt conveyor includes rotating components such as pulleys, rollers, shafts, and couplings, which resist acceleration due to their rotational inertia.

To account for this effect in a practical engineering calculation, an Equivalent Mass (meq) is used:

meq ≈ 1.1 × mtotal

The 1.1 factor is an empirical approximation; for critical applications, reflect individual component inertias to the motor shaft.

The acceleration force is then calculated as:

Facc = meq × a

This force represents the additional effort required to accelerate the belt, the conveyed load, and the rotating components.

Engineering Note:
For high-inertia systems (large pulleys, long conveyors, or low-speed drives), a detailed inertia calculation should be performed. For applications requiring precise motor acceleration analysis, full inertia reflection to the motor shaft should be performed.

6. Step 4 – Total Conveyor Force During Acceleration

Total force during acceleration is:

Ftotal = Frunning + Facc

  • Frunning = steady-state running force (friction + gravity)
  • Facc = acceleration force

Running force can be calculated using standard motor power and torque methods, as explained here:

How to Calculate Motor Power and Torque for a Belt Conveyor »


7. Step 5 – Convert Linear Force to Pulley Torque

Torque at the drive pulley is:

Tpulley = Ftotal × (D / 2)

This is the torque required at the pulley shaft during acceleration.


8. Step 6 – Check Motor Torque Capability

Motor torque during acceleration must satisfy:

Tmotor ≥ Tpulley / (i × Î·g)

If this condition is not met, the acceleration time must be increased (reducing a and Facc) or a larger motor selected.

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9. Worked Example – Industrial Belt Conveyor

Given:

  • Belt speed, v = 1.0 m/s
  • Total moving mass, mtotal = 580 kg
  • Running force, Frunning = 370 N
  • Drive pulley diameter, D = 0.25 m
  • Gearbox ratio, i = 20
  • Gearbox efficiency, ηg = 0.95

Assume acceleration time: t = 5 s

1. Acceleration:

a = 1.0 / 5 = 0.20 m/s2

2. Equivalent mass:

meq = 1.1 × 580 = 638 kg

3. Acceleration force:

Facc = 638 × 0.20 = 127.6 N

4. Total force:

Ftotal = 370 + 127.6 = 497.6 N

5. Pulley torque:

Tpulley = 497.6 × (0.25 / 2) = 62.2 N·m

6. Motor torque:

Tmotor = 62.2 / (20 × 0.95) = 3.27 N·m

This torque is within the capability of a standard 0.75 kW motor. A 5 s acceleration time is safe and acceptable.

10. Practical Engineering Guidelines

  • Typical conveyor acceleration time: 3–10 s
  • Heavy or long conveyors: 8–15 s
  • Ensure motor or VFD can deliver 150–200% rated torque during startup
  • Longer acceleration reduces belt tension and mechanical shock

11. Conclusion

Belt conveyor acceleration time is a balance between mechanical safety and operational efficiency.

By accounting for acceleration forces (including inertia) and verifying motor torque capability, engineers can select ramp times that protect belts, gearboxes, and motors while maintaining productivity.

This step-by-step method is suitable for most industrial belt conveyor systems and complements steady-state motor power calculations.

To continue the conveyor design process, also check startup belt tension calculations here: How to Calculate Belt Tension During Startup (Take-up & Safety Check) »

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