For engineers who already know the math—but still lose projects. For the last few years, I’ve been sharing technical guides here on Mechanical Design Handbook —how to size a motor, how to calculate fits, and (as you recently read) how to choose between timing belts and ball screws. But after 25 years in industrial automation, I realized something uncomfortable: Projects rarely fail because the math was wrong. They fail because: The client changed the scope three times in one week. A critical vendor lied about a shipping date (and no one verified it). The installation technician couldn’t fit a wrench into the gap we designed. University taught us the physics. It didn’t teach us the reality. That gap is why I wrote my new book, The Sheet Mechanic . This is not a textbook. It is a field manual for the messy, political, and chaotic space between the CAD model and the factory floor. It captures the systems I’ve used to survive industrial projec...
Designing a belt conveyor may look simple, but incorrect motor sizing is one of the most common causes of conveyor problems such as motor overheating, belt slipping, gearbox failure, or poor acceleration.
This article explains how to calculate the required motor torque and power for a belt conveyor using a clear step-by-step engineering method, including a realistic industrial example.
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1. Why Motor Power and Torque Calculation Matters
If the motor is:
- Undersized → motor stalls, trips, or overheats
- Oversized → unnecessary cost and poor energy efficiency
Correct calculation ensures reliable starting, stable running speed, acceptable motor temperature, and long mechanical life.
2. Basic Belt Conveyor Parameters
Figure 1: Inclined Conveyor Geometry. The motor must lift the load (Gravity) and overcome resistance (Friction).
Conveyor geometry
- Conveyor length, L (m)
- Inclination angle, θ (degree)
- Drive pulley diameter, D (m)
Load information
- Material mass on belt, mload (kg)
- Belt mass, mbelt (kg)
Operating conditions
- Belt speed, v (m/s)
- Coefficient of friction, μ
- Gearbox efficiency, ηg
- Motor efficiency, ηm
3. Step 1 – Calculate Total Moving Mass
The total moving mass on the conveyor is:
mtotal = mload + mbelt
In most medium-length conveyors, roller rotational inertia is either neglected or included later as a safety margin.
4. Step 2 – Calculate Required Conveyor Force
4.1 Horizontal Belt Conveyor
For a horizontal conveyor, the resisting force is mainly friction:
F = μ × mtotal × g
Where g = 9.81 m/s2.
4.2 Inclined Belt Conveyor
For an inclined conveyor, the required force consists of two components:
- Friction force (acts on belt and load)
- Gravity force (acts only on material load)
Total Force (F) = Ffriction + Fgravity
Ffriction = μ × mtotal × g × cos θ
Fgravity = mload × g × sin θ
Ffriction = μ × mtotal × g × cos θ
Fgravity = mload × g × sin θ
Engineering note:
In a continuous loop belt conveyor, the belt mass on the return side counterbalances the belt mass on the carry side. Therefore, the motor only consumes power to lift the material load, not the belt itself.
In a continuous loop belt conveyor, the belt mass on the return side counterbalances the belt mass on the carry side. Therefore, the motor only consumes power to lift the material load, not the belt itself.
5. Step 3 – Calculate Torque at the Drive Pulley
Torque at the drive pulley is:
Tpulley = F × (D / 2)
This is the minimum mechanical torque required at the pulley shaft.
6. Step 4 – Calculate Required Motor Torque
If a gearbox is used:
Tmotor = Tpulley / (i × Î·g)
Where i is the gearbox reduction ratio.
7. Step 5 – Calculate Required Motor Power
Motor power is calculated from force and belt speed:
P = (F × v) / (ηg × Î·m)
Power is expressed in watts (W). Divide by 1000 to obtain kilowatts (kW).
8. Worked Example – Industrial Belt Conveyor
Given:
- Conveyor length = 12 m (horizontal)
- Belt speed = 1.0 m/s
- Drive pulley diameter = 0.25 m
- Material load = 500 kg
- Belt mass = 80 kg
- Coefficient of friction (roller supported) μ = 0.03
- Additional accessories drag Faccessories = 200 N
- Gearbox ratio i = 20:1
- Gearbox efficiency ηg = 0.95
- Motor efficiency ηm = 0.90
- Service factor = 1.4
1. Total mass:
mtotal = 500 + 80 = 580 kg
2. Friction force:
Ffriction = 0.03 × 580 × 9.81 = 171 N
3. Total force:
F = 171 + 200 = 371 N
4. Pulley torque:
Tpulley = 371 × (0.25 / 2) = 46.4 N·m
5. Motor torque:
Tmotor = 46.4 / (20 × 0.95) = 2.44 N·m
6. Motor power:
P = (371 × 1.0) / (0.95 × 0.90) = 435 W
7. Design power:
Pdesign = 435 × 1.4 ≈ 610 W
Selected motor: 0.75 kW motor with gearbox
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9. Important Engineering Notes
9.1 Coefficient of Friction (μ)
- Roller supported belt: 0.02 – 0.05
- Slider bed (UHMW): 0.10 – 0.20
- Slider bed (steel): 0.20 – 0.35
Using roller friction values for a slider bed conveyor can undersize the motor by several times.
9.2 Starting Torque vs Running Torque
Static friction and loaded starts often require higher torque than steady running.
Design recommendation: Ensure the motor or VFD can deliver 150–200% of rated torque during startup.
For conveyors where startup conditions are critical, see our detailed guide on How to Calculate Starting Torque and Acceleration Power for a Belt Conveyor »
10. Conclusion
By separating friction and gravity effects and accounting for real-world losses, motor power and torque for a belt conveyor can be calculated accurately and reliably.
This step-by-step method is suitable for most industrial belt conveyors and provides a solid engineering basis for motor and gearbox selection.
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